Study Curve

lol, yeah the double the sum of 1 part was goofy... It took a minute to sink in.

Ok Lets see if this is right.
Jane guesses a number, so lets represent Jane's number as X.
Tom guesses a number that is double ( the sum of 1 and twice the number guessed by Jane (X).) Therefore we can represent Tom's guess with: 2(1+2x)
Then it says that the sum of both Jane and Tom's guess is 27. So then we can set up an equation adding the two together to get 27: X + 2(1+2x) =27
Than you solve that to find that X=5.
Leaving you to go back and plug 5 in for every X to find out what Jane and Tom guessed.
Jane guessed: 5
Tom guessed: 22
Horray, this is the first question I have ever answered on this website. I hope this helps. : )

The way you go about this type of problem is as follows (if I understand the question correctly but I am not quite sure what the double the sum of 1 has to do with):

You need to set up two equations, one with jane (x) and Tom (y) summed together to equal 27. ie x+y=27

Then you need to set up another equation that shows that Toms guess is twice what Jane's is: x=2y

You then plug the second equation into the first so you have all the same variables and solve:

2y+y=27
3y=27
y=9 so Jane's guess in 9 and Tom's guess which is double is 18. Add these two together and you get 27.

Does this sound right?