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Question: Molarity
- Posted By: jlspates
- Subject: Chemistry
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Molarity
What is the molarity of 12.5g NaHCO3 in 350mLsolution?
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- Posted By: juke
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First you need to get NaHCO3 into moles by dividing the 12.5g NaHCO3 by the molar mass (found on the periodic table) of the compound which is:
Na = 22.99
H = 1.008
C = 12.01
O = 16.00 (x3) = 48
So 12.5g NaHCO3/84.008 g/NaHCO3/1 mol NaHCO3
m = .149
Now that you have mole (m) you need to solve for the molarity (M) equation:
M = mol solute/L soln
M = .149/.350L = .425