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Question: Oxidation-Reduction Post-Lab
- Posted By: angelahaha
- Subject: Chemistry
- Group: Union AP Chemistry
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Oxidation-Reduction Post-Lab
How do I calculate the molarity of the MnO4- solution (and H2C2O4 solution) for each trial? (Questions 1 and 2 on the post-lab)
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- Posted By: dlemberg
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Post Lab Calc #1)
To calculate the molarity of the MnO4- ion you need to use the balanced redox reaction:
Molarity of MnO4-=1/5 moles Fe2+/L MnO4- solution
Take the M calculated for the 3 trials and report the average
Calc #2)
To calculate the molarity of the H2CO4
moles of H2C2O4 = 5/2 x moles of MnO4-
So
Molarity of the H2C2O4 = 5/2((molarity of the MnO4- x volume MnO4-)/volume of H2C2O4)
Take the average of the trials to get your answer
Calc #3)
Moles Fe2+ = M Fe2+x Volume of Fe2+
Moles of MnO4- = 1/5 moles Fe2+
Calc #4)
Moles H2C2O4 titrated = 5/2 moles of MnO4- titrated= 5/2 M MnO4- x Volume MnO4-