Question: how do you solve this kind of problems?

how do you solve this kind of problems?

(negative 10ab3rd power c5th power )2nd power (7a*10th power b c 3rd power)

Date Posted: August 28, 2007 Tagged Under: geometry
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n/a

(-10ab^3^5)^2(7???????????????????? what is after 7????????????????????

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n/a

67-8.2

Rating:
8.2

I would agree with juke. It's really a matter of home many a's you have with how many b's and c's. The exponent on the outside with the 2 is the hardest part. But a quick hint is that the thing that you wrote above in juke's notation is: (100a^2b^6c^10)(7a^10bc^3) = 700a^2a^10b^6bc^10c^3 and you can simplify from there by combining accoring to the product rule for exponents (see juke below). Really this should be tagged under algebra and not geometry, or did you see this in a geometry course?

Rating:
8.0

If I understand your question correctly this is what you are asking:

((-10ab^3c^5)^2)(-10ab^3c^5)

If this correct what you need to know are the following rules:

Product Rule: when multiplying two powers that have the same base you can add the exponents (x^4)*(x^3) is x^7

Power Rule: when you raise a power to a power you multiply the exponents. (x^4)^2 is x^8

Quotient Rule: when you divide two powers with the same base you subtract exponents. (x^4)/(x^3) is x

If you use these rules and break the problem into parts this should get you the result. I hope this helps.